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Can you number the vertices, edges and faces of a tetrahedron so that the number on each edge is the mean of the numbers on the adjacent vertices and the mean of the numbers on the adjacent faces?

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Tetra Square

ABCD is a regular tetrahedron and the points P, Q, R and S are the midpoints of the edges AB, BD, CD and CA. Prove that PQRS is a square.

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Triangles to Tetrahedra

Starting with four different triangles, imagine you have an unlimited number of each type. How many different tetrahedra can you make? Convince us you have found them all.

Icosian Game

Stage: 3 Challenge Level: Challenge Level:1

For the tetrahedron, I have:


I tested all Platonic solids: the tetrahedron, the cube, the octahedron, the dodecahedron and the icosahedron.

Graph for tetrahedron

For the tetrahedron, there was simple - there were only four points to study. I obtained more possible arrangements, corresponding to different solutions. The other, not shown is to go on the outside circuit up to the last-but-one point, than to go to the centre and finally at the starting point. There are different solutions only if the start - finish is represented on the figure, otherwise this solution is obtained from the first by a rotation.


For the cube, I worked on the applet on the Internet:

graph for cube

The strategy I used is the following: I go on the outer lines, up to the last-but-one point. Then I go through the inner one. I can use symmetrical combinations, obtaining more than one path.

Looking at the octahedron, I take the same strategy as for the cube => there are many combinations.

graph for octahedron

For the dodecahedron, I worked on the applet on the internet, taking the same strategy as for the cube, the difference is that here there are more layers.

graph fro dodecahedron

The last polyhedron I test is the icosahedron:

graph for icosahedron

Here, I worked in the same manner as before, obtaining the figure shown. There are naturally more combinations.