Is there an efficient way to work out how many factors a large number has?
Many numbers can be expressed as the sum of two or more consecutive integers. For example, 15=7+8 and 10=1+2+3+4. Can you say which numbers can be expressed in this way?
Helen made the conjecture that "every multiple of six has more
factors than the two numbers either side of it". Is this conjecture
Sue from CBEC Basingstoke sent the following
explanation to the first question:
We also received correct solutions from Jenny,
Greenian, Rachael, Jacqui and Sam, from The Mount School, and
Debbie from Forres Academy. Well done to you all.
53 x 92 = 4876
62 x 87 = 5394
24 x 57 = 1368
58 x 64 = 3712
52 x 34 = 1768
We'd like to hear from anyone who would like
to explain how they solved these problems.
We are always interested in the reasoning that has helped you reach