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Izak, who is home schooled, told us how
he went about tackling this problem:
After folding the flower and shading the triangle, I got another
square of paper the same size as the first one, but left it
unfolded. I traced the shaded triangle onto the corner of the
unfolded square of paper.
Then, I divided the unfolded square into $16$ equal squares.
Then, I used a ruler to divide one of the $16$ squares into
triangles the same size as the shaded one on the flower. I counted
the number of triangles in the $16$th of the square. There were
$32$ total triangles in that $16$th.
$32 \times 16 = 512$
So, there are $512$ triangles the size of the shaded one in the
original square of paper, therefore the shaded triangle is
$\frac{1}{512}$.
AI and JB from Gledhow Primary used a
similar method:
The solution to the question is $\frac{1}{512}$.
The explanation is, after we created the flower we marked the
triangle as we needed to find out what fraction this triangle was
out of the original square.
We unfolded the flower so we had the original square with the
marked triangle in the bottom corner.
We marked out $\frac{1}{4}$ of the square, we then quartered this
which gave us $\frac{1}{16}$.
We quartered again and got $\frac{1}{64}$.
Yet again we quartered giving us $\frac{1}{256}$.
The marked triangle was half of this so this time we halved and got
$\frac{1}{512}$.
Mark, also from Gledhow Primary, used
the same approach and he sent us a picture to help us see what he
did:
Joe, Sam, Ollie and Matthew from Keer
Mackie Primary used another slightly different method:
First we worked out there were $16$ squares in the paper.
Next we worked out that in the squares were $4$ triangles so we
found the product of $4$ and $16$ which was $64$.
Our next step was to find out how many of the smallest triangles
fitted in the biggest triangle. The answer was $8$ so we
timesed $8$ by $64$ and our final answer was $512$.
Thank you for your clear solutions. It's
not easy explaining how you worked on a problem when it involves
folding paper!