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## 'Curious Number' printed from http://nrich.maths.org/

Can you order the digits $1, 2, 3, 4, 5$ and $6$ to make a number which is divisible by $6$ ...

... so that when the final or last digit is removed it becomes a $5$-figure number divisible by $5$?

And when the final digit is removed again it becomes a $4$-figure number divisible by $4$?

And when the final digit is removed again it becomes a $3$-figure number divisible by $3$?

And when the final digit is removed again it becomes a $2$-figure number divisible by $2$, then finally a $1$-figure number divisible by $1$?