### Counting Factors

Is there an efficient way to work out how many factors a large number has?

### Repeaters

Choose any 3 digits and make a 6 digit number by repeating the 3 digits in the same order (e.g. 594594). Explain why whatever digits you choose the number will always be divisible by 7, 11 and 13.

### Oh! Hidden Inside?

Find the number which has 8 divisors, such that the product of the divisors is 331776.

# Indivisible

##### Stage: 3 Short Challenge Level:

Suppose there was one extra imaginary student in the production. Then, when they lined up in threes, the extra student could go with the left-over students to make another line. The same would happen with fours, fives and sixes.

Therefore, when there is one extra student, the number is divisible by $3$, $4$, $5$ and $6$. This means it is a common multiple of these numbers. The lowest common multiple of $3$, $4$, $5$ and $6$ is $60$, so there must be $60$ students with the extra.

Therefore the number of students (without the imaginary student) is $59$.

This problem is taken from the UKMT Mathematical Challenges.