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Weekly Problem 19 - 2011

Stage: 2 and 3 Short Challenge Level: Challenge Level:1

Tom travels for $10$ minutes longer than Tim, a time of $1$ hour and $50$ minutes. 

Travelling at a speed of $60$ mph (or $1$ mile per minute), Tom travels a distance of $110$ miles.
 
Tim travelled the sam distance in $1$ hour $40$ minutes ($1\frac{2}{3}$ hours), so his speed, in mph was $110\div 1\frac{2}{3} = 110\times \frac{3}{5} = 22\times 3 = 66$ mph.
 
 

This problem is taken from the UKMT Mathematical Challenges.

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