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Pride of Place

Stage: 3 Short Challenge Level: Challenge Level:1

The difference between $\frac{1}{3}$ and $\frac{1}{5}$ is $\frac{1}{3}-\frac{1}{5}= \frac{2}{15}$.

This section of the number line is divided into $16$ intervals, each of length $\frac{2}{15}\div 16 = \frac{1}{120}$.

The difference between $\frac{1}{4}$ and $\frac{1}{5}$ is $\frac{1}{4}-\frac{1}{5}= \frac{1}{20}= \frac{6}{120}$, and hence $\frac{1}{4}$is six smaller intervals from $\frac{1}{5}$. 

This problem is taken from the UKMT Mathematical Challenges.