### Consecutive Numbers

An investigation involving adding and subtracting sets of consecutive numbers. Lots to find out, lots to explore.

### Calendar Capers

Choose any three by three square of dates on a calendar page...

### Building Tetrahedra

Can you make a tetrahedron whose faces all have the same perimeter?

# Equal Length Powers

##### Stage: 3 and 4 Short Challenge Level:

Firstly, note that if $n \ge 10$, then $n^3 \ge 10n^2$ so $n^3$ will have at least one more digit than $n^2$.
For all $n< 10$, we have $n^2< 100$, so $n^2$ has either 1 or 2 digits, but $n^3$ has 3 digits for $n> 4$ since $5^3 = 125$, so we need only consider $n = 1, 2, 3$ or $4$.
For $n=1$ and $2$, $n^2$ and $n^3$ both have one digit; for $n = 4, n^2 = 16$ and $n^3 = 64$ both have two digits.
However for $n=3, n^2=9$ has one digit while $n^3 = 27$ has two digits.

This problem is taken from the UKMT Mathematical Challenges.
View the archive of all weekly problems grouped by curriculum topic