Copyright © University of Cambridge. All rights reserved.

'Tying the Rope' printed from

Show menu

There are six different possible ways of choosing two of the loose ends. Only two of these possibilities lead to a loop being made, therefore the probability that Sam holds one tied loop is $\frac{2}{6}=\frac{1}{3}$.

This problem is taken from the UKMT Mathematical Challenges.
View the archive of all weekly problems grouped by curriculum topic

View the previous week's solution
View the current weekly problem