Catherine and Poppy from Stoke by
Nayland Middle School made a good start on this problem, and
Kijung from Wind Point Elementary School found that:
Not all of Jamie's examples were right.
To be correct, one of the unit fractions must have a
denominator which is 1 more than the denominator of the
original unit fraction, and the other unit fraction must have a
denominator which is the product of the other two
denominators:
$$ \frac{1}{n} = \frac{1}{n+1}+\frac{1}{n(n+1)}$$
Here are some other examples that work:
$ \frac{1}{5} = \frac{1}{6}+\frac{1}{30}$
$ \frac{1}{6} = \frac{1}{7}+\frac{1}{42}$
$ \frac{1}{105} = \frac{1}{106}+\frac{1}{11130}$
$\frac{1}{8}$ can also be expressed as the sum of two unit
fractions in several ways:
$\frac{1}{8} = \frac{1}{9} +\frac{1}{72}$
$\frac{1}{8} = \frac{1}{10} +\frac{1}{40}$
$\frac{1}{8} = \frac{1}{11} + \frac{1}{n}$ is not
possible
$\frac{1}{8} = \frac{1}{12} +\frac{1}{24}$
Felix from Condover Primary acutely observed that unit
fractions with denominators which are prime numbers can only be
written in one way as the sum of two distinct unit
fractions.
Can unit fractions with composite denominators always be
written in more than one way as the sum of two unit
fractions?