The Not-so-simple Pendulum 2
Stage: 5 Challenge Level:

A simple pendulum released from rest from an angle $x$ of less
that $20^\circ$ is well-modelled by the linear differential
equation
$$m\frac{d^2 y}{dt^2} +k^2y=0$$
Can you work out the meaning of the various letters in the
equation, the units of the constant $k$ ,and find the general
solution to this equation?
Look at the solution: it keeps on oscillating forever. Clearly,
this is an unreasonble assumption, as real pendulums stop
swinging due to friction.
Here friction is modelled by a force term which is directly
proportional to the velocity of the object, acting in the
opposite direction to the motion. Do you think that this is a
good modelling assumption? What are its strengths and
weaknesses?
With this assumption, the differential equation becomes
$$m\frac{d^2 y}{dt^2} + \lambda \frac{d y}{dt}+k^2y=0$$
Can you see how this equation satisfies all of requirements of
a motion under friction? What are the units of $\lambda$, and
what features of the motion would contribute to it in practice?
It is assumed that $\lambda$ is constant: is this a reasonable
assumption?
Although this equation might look complicated it is still only
a second order differential equation with constant
coefficients, so can be solved using standard methods (and a
lot of algebra) to give
$$y = \exp\Big[-\frac{\lambda t}{2m}\Big]\Big[A\cos(\Lambda
t)+\sin(\Lambda t)\Big] \quad \Lambda =
\sqrt{\frac{k^2}{m}-\frac{\epsilon^2}{4m^2}}$$
Test your skills of differentiation by showing that this
equation indeed satisfies the differential equation. More
importantly, analyse the solution: how well does it model
friction? Consider in particular the amplitude and the
frequency of the damped oscillation. Does this meet with your
intuitive expectation?
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