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An Introduction to Proof by Contradiction
An introduction to proof by contradiction, a powerful method of mathematical proof.
Prime Sequences
Stage: 5
Challenge Level:
In 2004 an exciting new result was proved in Number Theory by two young mathematicians Ben Green and Terrence Tao. They proved that if you look in a long enough list of the prime numbers then you will be able to find numbers which form an arithmetic progression containing as many numbers as you choose! In this question we explore some of the interesting issues surrounding arithmetic progressions of prime numbers.
An $AP-k$ sequence is $k\geq 3$ primes in arithmetic progression.
See examples
A simple arithmetic progression of three primes starts at $3$ with common difference $4$, giving rise to the progression of prime numbers
$$
3, 7,11
$$
This is an example of $AP-3$. Note that the sequence stops here because $11+4=15$, which is not a prime number. Another short arithmetic progression starts at $7$ with common difference $6$
$$
7, 13, 19
$$
This problem involves several linked parts leading up to a final challenge. Try some of the earlier questions to gain insights into the final challenge. These can be attempted in any order. You might find that you naturally ask yourself questions which are found later in the list of questions and you might find that one part helps in the consideration of another part. Of course, you are welcome to go straight to the final challenge. However, you might also wish to start with one of the earlier challenges and see how many of the other challenges you naturally discover whilst exploring the underlying mathematical structure.
Consider some of these three questions first:
Question A
Can you find an arithmetic progression of four primes?
Question B
How many prime APs beginning with $2$ can you find?
Question C
How many other arithmetic progressions of prime numbers from the list of primes below can you find?
Next consider some of these three questions:
Question A
Why is $3, 5, 7$ the only prime AP with common difference $2$?
Question B
What is the maximum length of a prime AP with common difference of $6$?
Question C
If the common difference of a prime AP is $N$ then the maximum length of the prime AP is $N-1$.
Now consider some of these three questions:
Question A
What is the maxiumum length of a prime AP with common difference $10$?
Question B
What is the max length of a prime AP with common difference $100, 1000, 10000$ ?
Question C
What are the possible lengths of prime APs with common difference $2p$, where $p$ is prime? Consider $p=3$ and $p> 3$ separately.
When you have thought about some of the previous problems you might like to try the
final challenge
Prove that if an AP-$k$ does not begin with the prime $k$, then the common difference is a multiple of the
primorial
$k$#$ = 2\cdot 3\cdot 5 \cdot \dots \cdot j$, where $j$ is the largest prime not greater than $k$.
Once you have solved this, why not try to think of some other questions about prime APs to ask?
In doing these problems you might like to see this
list of primes
2
3
5
7
11
13
17
19
23
29
31
37
41
43
47
53
59
61
67
71
73
79
83
89
97
101
103
107
109
113
127
131
137
139
149
151
157
163
167
173
179
181
191
193
197
199
211
223
227
229
233
239
241
251
257
263
269
271
277
281
283
293
307
311
313
317
331
337
347
349
353
359
367
373
379
383
389
397
401
409
419
421
431
433
439
443
449
457
461
463
467
479
487
491
499
503
509
521
523
541
547
557
563
569
571
577
587
593
599
601
607
613
617
619
631
641
643
647
653
659
661
673
677
683
691
701
709
719
727
733
739
743
751
757
761
769
773
787
797
809
811
821
823
827
829
839
853
857
859
863
877
881
883
887
907
911
919
929
937
941
947
953
967
971
977
983
991
997
1009
1013
1019
1021
1031
1033
1039
1049
1051
1061
1063
1069
Fibonacci sequence
.
Mathematical induction
.
Prime numbers
.
Arithmetic sequence
.
Interactivities
.
Making and proving conjectures
.
Mathematical reasoning & proof
.
Dynamic geometry
.
Summation of series
.
Generalising
.