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If the friends meet in Bergerac, the total distance travelled will be $$87+79+61+58 \; \text{km} = 285\; \text{km}$$
Bergerac        
$87$ Bordeaux      
$79$   Langon    
$61$     Libourne  
$58$       Marmande




If the friends meet in Bordeaux, the total distance travelled will be $$87+47+31+84 \; \text{km} = 249\; \text{km}$$
Bergerac        
$87$ Bordeaux      
  $47$ Langon    
  $31$   Libourne  
  $84$     Marmande




If the friends meet in Langon, the total distance travelled will be $$79+47+54+37 \; \text{km}=217\; \text{km}$$
Bergerac        
  Bordeaux      
$79$ $47$ Langon    
    $54$ Libourne  
    $37$   Marmande



If the friends meet in Libourne, the total distance travelled will be $$61+31+54+65 \; \text{km}=211\; \text{km}$$
Bergerac        
  Bordeaux      
    Langon    
$61$ $31$ $54$ Libourne  
      $65$ Marmande



If the friends meet in Marmande, the total distance travelled will be$$58+84+37+65 \; \text{km}=244\; \text{km}$$
Bergerac        
  Bordeaux      
    Langon    
      Libourne  
$58$ $84$ $37$ $65$ Marmande


So the friends should meet in Libourne.



This problem is taken from the UKMT Mathematical Challenges.
You can find more short problems, arranged by curriculum topic, in our short problems collection.