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Weekly Problem 8 - 2009

Stage: 3 Short Challenge Level: Challenge Level:1

12.

Instead of confusing ourselves with the positions of the L's, we only need to look at where the G and I will go, and the L's will just go in the remaining positions. Starting with the G, we can put it in one of 4 places. Then there are 3 remaining places to put the I. So the number of words is $4 \times 3=12$.

This problem is taken from the UKMT Mathematical Challenges.

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