There were three Friday 13
^{th}s in 1998,
this is the greatest number that can occur in any one year, and
there must be at least one each year.

Here is the solution from the Strabane Grammar School Key Stage 3 Maths Club:

There are 14 possibilities to consider. These are detailed in
the table below together with the number of Friday 13 ^{th}
s appearing in each year:

1st January falls on: | Not a Leap Year | Leap Year |

Monday | 2 | 1 |

Tuesday | 2 | 1 |

Wednesday | 1 | 2 |

Thursday | 3 | 2 |

Friday | 1 | 2 |

Saturday | 1 | 1 |

Sunday | 2 | 3 |

Calendar calculations are very tedious if you have to do everything by counting and it is quicker to use modulus arithmetic.

To use the fact that 31 days is 4 weeks and 3 days, we say 31 is congruent to 3 modulo 7 and we write:-

31 3 (mod 7).

So:

31/7 = 4 remainder 3 or 31 3 (mod 7).

30/7 = 4 remainder 2 or 30 2 (mod 7).

29/7 = 4 remainder 1 or 29 1 (mod 7).

28/7 = 4 remainder 0 or 28 0 (mod 7).

Chin Siang explains the method as follows:

X can stand for any day (Monday, Tuesday, Wednesday, ...)

January | X | X |

February | X+3 | X+3 |

March | X+3+0 (not leap year) | X+3 |

April | X+3+0+3 | X+6 |

May | X+3+0+3+2 | X+1 |

June | X+3+0+3+2+3 | X+4 |

July | X+3+0+3+2+3+2 | X+6 |

August | X+3+0+3+2+3+2+3 | X+2 |

September | X+3+0+3+2+3+2+3+3 | X+5 |

October | X+3+0+3+2+3+2+3+3+2 | X |

November | X+3+0+3+2+3+2+3+3+2+3 | X+3 |

December | X+3+0+3+2+3+2+3+3+2+3+2 | X+5 |

Looking at the table above, you will notice that X, X+1, X+2, X+3, X+4, X+5 and X+6 all occur at least once and at most three times. Thus, sometime in the year the thirteenth of the month will be on each of the different days of the week at least once and at most three times. For the thirteenth to be a Friday the first of the month must be a Sunday. This can only occur three times in the year, in February, March and November, when the 1st January is a Thursday.