Chieh Lung from Kolej Tuanku Jaafar
school made a good start on this:
$(x+y-1)(x^2+y^2)=0$. The solutions of this are like solving a
quadratic equation, when solutions are when at least one of the
brackets is equal to zero. Here the first bracket is the top line,
and the second only has solutions at $(0,0)$ as we are in the real
$x^3 + 3xy + y^3 = 1$. This must also be a product of the lines
and points. But I cannot find them.
Good start Chieh, Adam finished off your
This effect could be created many times by choosing two lines,
and then multiplying them by points (say $x^2+y^2=0$).