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## 'It's Only a Minus Sign' printed from http://nrich.maths.org/

In this problem we shall see how
a simple minus sign in a differential equation can completely
change the character of the solution.
Two particles are released from $x = 1$ at time $0$ and their speed
at any point x will be given by these two differential equations:

particle $A \quad \quad$ |
$\frac{dx}{dt}=x$ |

particle $B$ |
$\frac{dx}{dt}=-x$ |

Without solving the equations, can you describe how the
particles will move? Draw a sketch graph of the path you expect the
particles to take.

Now solve the equations to see if you were correct.

Next suppose that two more particles are released with a
positive velocity at time $0$ from the origin and move according to
these equations, in which v is the velocity of each particle:

particle $C \quad \quad$ |
$\frac{dv}{dt}=x$ |

particle $D$ |
$\frac{dv}{dt}=-x$ |

Without solving the equations, can you provide a clear
description of the subsequent motion of the particles?

Would releasing the particles with a negative velocity from the
origin have a significant effect on the type of motion which
results?

Could you find initial starting points and velocities which would
give rise to motions in which the particles slow down and
stop?