$2\wedge 3\wedge 4$ could be $(2^3)^4$ or $2^{(3^4)}$. Does it make any difference? For both definitions, which is bigger: $r\wedge r\wedge r\wedge r\dots$ where the powers of $r$ go on for ever, or $(r^r)^r$, where $r$ is $\sqrt{2}$?

Tens

Stage: 5 Challenge Level:

You could write $9^n$ as $(10-1)^n$ and consider the terms of the binomial expansion...

Or you could use Modular Arithmetic - there's a useful introduction here.