Why do this
problem?
This problem
starts very easily but becomes harder with the second and third
matrices. The last part, discovering how to work out how the matrix
is made up, is really challenging because there are so few clues in
the final matrix.
Possible approach
You could start by doing the first magic matrix on the board
together. It is not very surprising when all get the same answer!
If anyone gets $11$, for example, instead of $10$, you can check
quickly that they are doing it correctly. Then let the class try
another couple for themselves, perhaps suggesting that they make
sure they choose different numbers from their neighbours. Those
confident with decimals and fractions could try then the next two
matrices.
This sheet
gives six copies of the first matrix and two copies each of the
second and third ones.
After that you could introduce the next matrix with the magic
total of $100$, and then continue to show the class how it is built
up.
This sheet has the
illustrations from the problem for this.
After this, the group could be challenged to work in pairs
making their own magic matrices. It is advisable to limit these to
magic totals between $12$ and $200$.
This sheet has six copies
of the frame for the matrix. However, squared paper can easily be
used instead.
The final challenge, to discover what numbers were used to
make any of the original three matrices is hard, and could,
perhaps, be reserved for the most able learners.
Key questions
Why not try one of the other matrices?
How can the same number result whichever choices are
made?
What number are you choosing for your own matrix?
How are you going to divide it into eight numbers?
You could start with the numbers in the top row of the
matrix.
What two numbers could be added together to make $1$?
Possible extension
When the numbers that were used to make up all three of the
original matrices have been found, learners could make a larger
matrix such as one on a $5$ by $5$ grid.
Possible support
Suggest sticking with the first matrix and then trying the one
which adds to $100$.