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We had lots of solutions to this problem but not many of you told us how you got your solutions. Luis and Freddie, who go to Newton Prep, sent in well-explained solutions. Here is what Luis wrote:

The first thing I worked out is that the letter at (4,2) is not symmetrical in any way, the only letter that isn't symmetrical in any way is the letter P.

Then I worked out that at (0,2) and (1,2) are the ends of the alphabet and had to be A and Z but I needed to know which one went where so I looked at the clues. One said that (0,2) and (2,0) have rotational symmetry which means that A is on (1,2) and Z is on (0,2).

Then I saw the clue that said that (3,3), (3,2) and (3,1) are all consecutive in the alphabet, because the A and the Z are already used, it has to be C, D and E because it says that (3,3) is made of only curved lines.

Then I saw that one of the clues said that (2,0) is only made of curved lines, so (2,0) is the S.

(4,2) is not symmetrical in any way so (4,2) is a P.

The first clue says that (1,1) and (1,3) have a vertical line of symmetry, another clue says that (1,1) also has a vertical line of symmetry, which means that (1,1) is a X and (1,3) is a Y, which leaves the B which is at (2,1) because a clue says that at (2,1) there is a letter with a horizontal line of symmetry.

Many children from Stradbroke Primary School sent an image of their solution. Here is George's:

Well done!

Rose and Thomas from Minterne Junior School wrote the followingWe know that (1,1) = X because it has both horizontal and vertical symmetry.

A had to be (1,2) becuase it has vertical symmetry and is at one end of the alphabet.

Y was placed at (1,3) because it has vertical symmetry.

We knew that X, S and Z have rotational symmetry, but X has to be at (1,1), so Z was placed at (0,2) because it is also at the other end of the alphabet, and S at (2,0) becuase it has

curved lines.

We put C (3,3), D (3,2) and E at (3,1) because they are consecutive.

This works because C at (3,3) also had to consist of curved lines, and E (3,1) had

to have just straight lines.

Finally, we put B on (2,1) becuase it has horizontal symmetry, and P at (4,2) becuase it has no lines of symmetry.

Well don e, you two for giving such a clear description as to how you came to your answer.