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Weekly Problem 23 - 2007

If two of the sides of a right-angled triangle are 5cm and 6cm long, how many possibilities are there for the length of the third side?

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Weekly Problem 1 - 2011

Use facts about the angle bisectors of this triangle to work out another internal angle.

Weekly Problem 14 - 2007

Stage: 3 and 4 Challenge Level: Challenge Level:1

$110^{\circ}$

As $\angle QPR=40^{\circ}$, $\angle PQR+\angle PRQ=180^{\circ}-40^{\circ} =140^{\circ}$.

So $\angle SQR+\angle SRQ=140^{\circ}/2=70^{\circ}$. Therefore $\angle QSR =180^{\circ}-70^{\circ}=110^{\circ}$.

This problem is taken from the UKMT Mathematical Challenges.

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