Answer: $x^4 \lt x^3 \lt x^2 \lt x^3 + x^2 \lt x^2 + x$

$x^2 + x \gt x^2$ because $x$ is positive

$x^3 = x^2\times x \lt x^2$ because $x\lt1$

$x^3 + x^2 \gt x^3, x^2$ because $x^3$ and $x^2$ are positive

$x^3 + x^2 = x\times\left(x^2 + x\right) \lt x^2 + x$ (or $x^3 + x^2 = x^2 + x^3 \lt x^2 + x$ because $x^3\lt x$)

And $x^4 =x\times x^3 \lt x^3$

So $x^4 \lt x^3 \lt x^2 \lt x^3 + x^2 \lt x^2 + x$