### Chocolate

There are three tables in a room with blocks of chocolate on each. Where would be the best place for each child in the class to sit if they came in one at a time?

### F'arc'tion

At the corner of the cube circular arcs are drawn and the area enclosed shaded. What fraction of the surface area of the cube is shaded? Try working out the answer without recourse to pencil and paper.

### Do Unto Caesar

At the beginning of the night three poker players; Alan, Bernie and Craig had money in the ratios 7 : 6 : 5. At the end of the night the ratio was 6 : 5 : 4. One of them won $1 200. What were the assets of the players at the beginning of the evening? # Rod Fractions ##### Stage: 3 Challenge Level: Terry from Warren Comprehensive School sent us his solution to this problem: The Red rod is$\frac{1}{4}$of the Brown rod. The Green rod is$\frac{2}{3}$of the Blue rod. The Pink rod is$\frac{2}{5}$of the Orange rod. The Green rod is$\frac{3}{10}\$ of the Orange rod.

The method for working out the short rod as a fraction of the long rod is:

When you complete the rows of rods so that they match, the number of long rods is the numerator for the fraction and the number of short rods is the denominator for the fraction.

It is easy to see why this works when you use only one long rod - you can return to the interactivity to see why this works in general.

Well done Terry.