Tamsin from Ringmer Primary School correctly states that

With 2 discs you win approximately half the time.Congratulations to Thomas from Dalton School in New York for his correct solution:

The probability of obtaining the same colour with two discs is 1/2 because there are two ways of obtaining this result (red-red, green-green) and there are four combinations in total (red-red, green-green, red-green, and green-red). Hence, the probability is 2/4, which simplifies to 1/2.For three discs, the probability is 1/4 using the same logic - there are two ways of obtaining the same colour and eight combinations in total (2 $\times$2 $\times$2, or 2$^3$).

For four discs, the probability is 1/8 because there are two ways of obtaining the same colour and sixteen combinations in total (2 $\times$2 $\times$2 $\times$2, or 2$^4$).

The general formula for the probability of flipping n discs and obtaining the same colour is:

$2/ 2^n$ or $1/ 2^{(n-1)}$.

Emma from St. Paul's Girls' School also found that

The probability of winning for n discs = 1/(2 to the power n-1)Adan from Bancroft's uses Pascal's Triangle to help him determine the total number of possible combinations:

Using Pascal's Triangle you can work out the chances of them
being all the same.

Firstly you must match the number of discs with the line of that number but one higher.

For example, let's use 3 discs:

On the fourth line of the triangle it says "1 3 3 1".

You must then add them all together, (that makes 8) this is
the bottom of your fraction.

The left of the line is the number of combinations possible
for them all being red.

The right is the number of combinations possible for them all
being green.

The middle ones are the number of combinations possible for
there being one of one colour and two of the other.

When you put one on the top and one on the bottom of your
fraction you get the chances of that combination (eg.: the chances
of there being one red and two green is 3/8).