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To four places of decimals \[\sqrt{56} = 7.4833\;\mbox{ and }\; \sqrt{58} = 7.6158\]

If $\sqrt{56} < \frac{p}{q} < \sqrt{58}$, then $ 56q^2 < p^2< 58q^2$

Try different values of $q$, and remember $p$ is a whole number.