# OK! Now Prove It

##### Stage: 5 Challenge Level:

Notice that $$1^2 = {1\times 2\times 3 \over 6}$$ $$1^2 + 3^2 =
{3\times 4\times 5 \over 6}$$ $$1^2 + 3^2 + 5^2 = {5\times 6\times
7 \over 6}.$$ Make a conjecture about the sum $$1^2 + 3^2 + 5^2 +
\dots + (2n - 1)^2$$ and prove your conjecture.