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'Sine and Cosine for Connected Angles' printed from http://nrich.maths.org/
The diagram shows a nine-point pegboard. We'll take the board radius as one (in other words it's a unit circle).
Looking at triangle $OAM$, why is $AM$ equal to $\sin40^\circ$?
Looking at triangle $OAB$, why is $AB$ equal to $2\sin20^\circ$?
Looking at triangle $ABM$, why is $AM$ also equal to $AB\cos20^\circ$ which works out as $2\sin20^\circ$ $\cos20^\circ$
So it looks like the same $AM$ length value can be calculated by using $\sin40^\circ$
and also calculated by using $2\sin20^\circ\cos 20^\circ$
Now switch to a $10$ point pegboard and find the two ways to calculate the $AM$ length on that board.
How about on a $12$ point board? What general result is emerging?
Draw a diagram and use it to provide reasoning which accounts for that general result.
For printable sets of circle templates for use with this activity, please see Printable Resources page
Many thanks to Geoff Faux who introduced us to the merits of the 9 pin circular geo-board.
The boards, moulded in crystal clear ABS that can be used on an OHP (185 cm in diameter), together with a teacher's guide, are available from Geoff at