You may also like

problem icon

Pericut

Two semicircle sit on the diameter of a semicircle centre O of twice their radius. Lines through O divide the perimeter into two parts. What can you say about the lengths of these two parts?

problem icon

Circumspection

M is any point on the line AB. Squares of side length AM and MB are constructed and their circumcircles intersect at P (and M). Prove that the lines AD and BE produced pass through P.

problem icon

Quads

The circumcentres of four triangles are joined to form a quadrilateral. What do you notice about this quadrilateral as the dynamic image changes? Can you prove your conjecture?

Right Angles

Stage: 3 and 4 Challenge Level: Challenge Level:2 Challenge Level:2

Samantha and Shummus both realised that in order to create a triangle with a right angle, the band had to go through the centre of the circle. Shummus writes:

I noticed that the bands had to be started in the centre.

Xianglong Ni notes that:

If we have 9 points on the circle then you can't create a right-angle using the points. This is so because a right angle is inscribed in a semicircle; It is facing a diameter. But you can only create a diameter when there is an even amount of points on the circle. If the number of points on the circle is even then yes. If the number is odd then no.

Rachel from Newstead sent us a few diagrams to illustrate examples of right-angled triangles in circles with an even number of points.

8 rt right-angled triangleright-angled triangle in 10 pt circle

Indika of Helena Romanes 6th Form College sent us her explanation for why the band must go through the centre of the circle:

The only way that a right angle triangle can be created between 3 points round the edge is when the angle subtended at the centre by two of the points is 180 degrees, this therefore proves that two of the points have to be opposite each other (this means having an equal number of pegs).

This is because the angle subtended at the centre by two points are exactly double the angle subtended at the edge by the same points. This rule will apply to all circles, i.e. there will be a right angled triangle if two pegs are placed opposite each other.

If you haven't met this idea before, you may want to look at another problem from August 2005, Subtended angles

Here are another couple of examples of right-angled triangles using the same eight-point and ten-point circles that Rachel used:

8pt circle, right angle triangle10pt circle, right angle triangle