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List any 3 numbers. It is always possible to find a subset of adjacent numbers that add up to a multiple of 3. Can you explain why and prove it?

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### Weekly Problem 2 - 2013

Weekly Problem 2 -2013

# Partitioning Revisited

##### Stage: 3 Challenge Level:

You may like to evaluate $(x + 4)^2, (x + 5)^2, (x + 6)^2$... before proceeding to $(x + a)^2$.