Take a look at the multiplication square below:
Pick any 2 by 2 square and add the
numbers on each diagonal.
For example, if you take:
the numbers along one diagonal add up to $77$ ($32 + 45$)
and the numbers along the other diagonal add up to $76$ ($36 +
40$).
Try a few more examples.
What do you notice?
Can you show (prove) that this will always be true?
Now pick any 3 by 3 square and add
the numbers on each diagonal.
For example, if you take:
the numbers along one diagonal add up to $275$ ($72 + 91 +
112$)
and the numbers along the other diagonal add up to $271$ ($84 + 91
+ 96$).
Try a few more examples.
What do you notice this time?
Can you show (prove) that this will always be true?
Now pick any 4 by 4 square and add
the numbers on each diagonal.
For example, if you take:
the numbers along one diagonal add up to $176$ ($24 + 36 + 50 +
66$)
and the numbers along the other diagonal add up to $166$ ($33 + 40
+ 45 + 48$).
Try a few more examples.
What do you notice now?
Can you show (prove) that this will always be true?
Can you predict what will happen
if you pick a 5 by 5 square, a 6 by 6 square ... an n by n square,
and add the numbers on each diagonal?
Can you prove your
prediction?
A poster of this problem can be found
here.