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'Nine, Ten and One' printed from http://nrich.maths.org/
We are given that 2n + e
= 8 and t + e + n
=10. Subtracting the first equation from the second gives t - n
cannot equal 1, the minimum value of t
is 4 but this gives n
= 2, e
=4 which is not allowed.
= 5 then n
= 3 and e
= 2, which is allowed.
> 5 then n
>3 and e
is not a positive whole number, so 5 is the only possible value of t
This problem is taken from the UKMT Mathematical Challenges.