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Why do this problem?
makes a very good introduction to algebra, however, it also begins very simply so everyone can make a reasonable start.
You could start by giving all the group some interlocking cubes and asking them to make a stick of seven. Then tell them to break their stick into two pieces and hold one piece in each hand. Ask how they have done this and write the various ways on the board and then enquire if there are any other ways that it could have been done. Is there a way that the results can be organised better?
This may be the time to show the group how to make a simple table to record their results.
Some learners may claim that $2 + 5$ is the same as $5 + 2$. "Not always!" is the answer to this. Of course, numerically they are identical, but the context is also important. A good example for when this is not so is this. If five people are sitting down to a meal and two more turn up, it is quite possible there will be enough food for them. If however, two are starting their meal it is
very unlikely that there will be enough food for five more! In this case, is $5 + 2$ the same as $2 + 5$? Just because the answer is the same, it does not mean that the question is the same!
After the introduction, learners could work in pairs on finding the number of ways that sticks of six, eight and nine cubes can be broken into two pieces. Then they should record their findings. Supply squared paper for those who wish to record using it.
When learners feel ready to generalise they can go on to working out the number of ways with $20$, $50$ and $100$ cubes and then ANY number of cubes.
At the end of the lesson all can come together to discuss their findings. They can be asked how they knew they had found all the ways of breaking a stick into two pieces. Those who know a good way of expressing "any number" can explain their reasoning.
How are you going to record what you have done?
How do you know you have found all the ways of breaking it into two pieces?
If you break it into $0 + 7$, does this give you two pieces?
How many ways do you think you can break $20/50/100$ cubes?
Can you see a connection between the total number of cubes and the number of ways you can break the stick into two pieces?
How could you express that "for any number"?
Learners who can generalise the first part of the problem could then go on to exploring the second part - if all the cubes are the same colour, looking at the difference between odd and even numbers.
Then they could try a different problem in which generalisation is required such as Sticky Triangles
Suggest working with the interlocking cubes and recording on squared paper.