I have forgotten the number of the combination of the lock on my briefcase. I did have a method for remembering it...
Sam displays cans in 3 triangular stacks. With the same number he could make one large triangular stack or stack them all in a square based pyramid. How many cans are there how were they arranged?
Here is a collection of puzzles about Sam's shop sent in by club members. Perhaps you can make up more puzzles, find formulas or find general methods.
Siobhan, Ruth, Ruth and Toby from Risley Lower Grammar Primary School, Joe from Hove Park Lower School, Nathan, Dulan and Pavan from Wilson's Grammar School and Thomas from PS6 in New York noticed that:
Students from the Tower Hamlets Enriching Maths project also worked on this problem:
Jinquan from The Chinese High School in Singapore explained that:
$T_{250}+T_{250}$ is $250 \times251$, and more generally $T_{n}+T_n = n(n+1)$
Hence, $T_n=n(n+1)/2$
which gives $T_{250}=31375$,
Consider $4851$.
If $4851$ is a triangular number, $9702$ can be expressed as $n(n+1)$.
By solving the quadratic equation or by estimating, we get $n = 98$, and hence $4851 = T_{98}$
In general, a number $x$ is a triangular number if and only if $n(n+1)=2x$ is solvable for positive integers of $n$.
Consider $6214$.
If it is a triangular number, $12428$ can be expressed as $n(n+1)$.
By solving the quadratic equation or by estimating, we see that there are no solutions in positive integers.
Hence $6214$ is not a triangular number.
Consider $3655$.
If it is a triangular number, $7310$ can be expressed as $n(n+1)$.
By solving the quadratic equation or by estimating, we get $n = 85$, and hence $3655 = T_{85}$