Let the large circles have radius R. $$ Area A = 2 x \pi x ({1
\over 2}R)^2 = 1/2 \pi R^2 $$ $$ Area B = 3 x {1 \over 2} x R^2 x
{\sqrt 3\over 2} = {3\over 4} \sqrt 3 R^2$$ $$ Area C = (2 R^2) -
\pi R^2 = (4 - \pi)R^2 $$ $$ Area D = 2 x {1 \over 2} x R^2 = R^2
$$ $$ Area E = \pi R^2 (\sqrt 2 R)^2 = (\pi - 2)R^2 $$

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*This problem is taken from the UKMT Mathematical Challenges.*

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