The familiar Pythagorean 3-4-5 triple gives one solution to (x-1)^n
+ x^n = (x+1)^n so what about other solutions for x an integer and
n= 2, 3, 4 or 5?
Find the positive integer solutions of the equation (1+1/a)(1+1/b)(1+1/c) = 2
Find all 3 digit numbers such that by adding the first digit, the
square of the second and the cube of the third you get the original
number, for example 1 + 3^2 + 5^3 = 135.
Square both sides. Multiply throughout by x. Rearrange to form the quadratic inequality:
Use the quadratic formula to solve this inequality. From the graph of $y =x^2 -14x + 1$ we see that the solution is $7-4\sqrt 3 < x < 7+4\sqrt 3$ or approximately $0.072< x< 13.928.$
Click on the pdf links to read Eric's, Minhaj's, Manolis's and Sasi's solutions.