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Show that the edges $AD$ and $BC$ of a tetrahedron $ABCD$ are mutually perpendicular when: $AB^2+CD^2 = AC^2+BD^2$. |
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Show that the edges $AD$ and $BC$ of a tetrahedron $ABCD$ are mutually perpendicular when: $AB^2+CD^2 = AC^2+BD^2$. |