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We have had the following solution from Matthew, David and Jack at St. Nicolas School, Newbury. They thought there was a problem with number 6 but there isn't!

Our solutions to the missing coordinates are:

  1. (2,11), (0,9), (2,7) ..............(4,9)
    which had both rotational and line symmetry.
  2. (3,7), (3,4), (8,4) ..............(8,7)
    which had both rotational and line symmetry.
  3. (18,3), (16,5), (12,5) ..............(10,3)
    which had line symmetry.
  4. (13,12), (15,14), (12,17) ..............(10,15)
    which had both rotational and line symmetry.
  5. (7,14), (6,11), (7,8) ..............(8,11)
    which had both rotational and line symmetry.
  6. (15,9), (19,9), (16,11) ..............(12,11)
    which had rotational symmetry.
  7. (11,3), (15,2), (16,6) ..............(12,7)
    which had both rotational and line symmetry.
  8. (9,16), (2,9), (9,2) ..............(16,9)
    which had both rotational and line symmetry.

We plotted these 8 sets of coordinates, which made a symmetrical star.

Symmetical 4-pointed star on graph paper.


We also heard from George and Thalia from Hoyle Court Primary School, Baildon who worked together to complete the puzzle.  Their teacher wrote:

They worked out the missing co-ordinates for the quadrilaterals then tried to produce the final symmetrical shape.
At first their shape was not symmetrical. They realised it should be a star and corrected the two inaccurate co-ordinates.
Then went back and drew the original two quadrilaterals again using the amended co-ordinates from the star.
Great teamwork!!

Here are photos of their symmetrical star and some of their initial quadrilaterals: