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## 'Trick or Treat' printed from http://nrich.maths.org/

Emily and Tristan from St James' School
answered the whole problem as follows:

I think the solution to this problem is that the most likly one to
pick out is the mice because there are 9 mice and only 5 frogs and
4 worms, also to pick out at least one of each you would need to
pick out 15 sweets because the first 9 could be mice and the next 5
you pick out could be frogs and after that you're definitely going
to pick out a worm. As well as that if Trixie picked out a mouse
there would still be 8 mice left so her brother is still more
likely to pick out a mouse.

Well done to Connor from Eastwood Primary,
pupils at Girton Glebe Primary, and Samm for also getting all or
parts of the solution correct.