There were several solutions sent in to this problem, which was about substituting numbers for letters. Most people interpreted the problem in the same way, that different letters could not share the same value, in other words H and E had their own value and E could not be the same as H. Well done to each of the solution finders.

**Christina Ivanova**, from Marlborough Primary
School explained her strategy for keeping track of the digits she
used and to help her discover the value for each letter. *I saw
there were 10 different digits which meant there would be 10
different digits. From then on I started guessing the numbers,
crossing off the digits as I used them. My final solution
was:*

Christina's solution was shared by **Ece Tugc and Simin
Araz** (Irmak Primary School, Istanbul, Turkey)

A second solution was found by **Sophie and
Annabelle** (Annesley College, Adelaide, Australia),
**Sinan Ersanli** (from the sixth grade of Irmak
Primary School, Istanbul, Turkey) and **Ece Demir**
(also in sixth grade, in the Irmak, Private Primary School). Sophie
and Annabelle wrote it out in the following way:

T= 7

H = 4

F = 2

L = 5

R = 6

O = 0

V = 3

N = 8

E = 1

This is the sum with the letters replaced with the digits

**Simin Araz** from Irmak Primary School in
Istanbul, Turkey found a third solution to the problem:

And Rose from Claremont Primary School in Tunbridge Wells submitted this solution, which was different to all the other ones that we had received.

Well done to you all.

**Are there any more solutions that could be found for
this problem?**

**Are there any factors that limit the number of possible
solutions?**

**Can anybody suggest a strategy for finding all the
possibilities?**