Answer: $\dfrac{3}{2} \qquad \dfrac{5}{3} \qquad \dfrac{7}{4} \qquad \dfrac{9}{5} \qquad \dfrac{11}{6}$


$\frac{11}{6} = 1\frac56$ is $\frac16$ below $2$

$\frac{5}{3} = 1\frac23$ is $\frac13$ below $2$

$\frac{7}{4}$ is $\frac14$ below $2$

$\frac95$ is $\frac15$ below $2$

$\frac32$ is $\frac12$ below $2$

$\therefore \frac{3}{2} \lt\frac{5}{3} \lt\frac{7}{4} \lt\frac{9}{5} \lt\frac{11}{6}$