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'Weekly Problem 19 - 2014' printed from http://nrich.maths.org/

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Adjacent angles on a straight line add up to 180°, so ∠GJF = 180° -111° = 69°.
In triangle FGJ, GJ = GF so ∠GFJ = ∠GJF. Therefore ∠FGJ =(180 - 2 x 69)° = 42°.  s FGHI is a rhombus, FG = FI and therefore ∠GIF = ∠FGI = 42°.

Finally, from triangle FJI, ∠JFI = (180 - 111 - 42)° = 27°.



This problem is taken from the UKMT Mathematical Challenges.

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